Tentukan hasil dari perpangkatan berikut a. 5+3×2⁴

b. 1/2 (6³— 4²)
c. 8+3×(— 3)⁴
d. (6⁴ — 4⁴): 2
e.(1/2)⁴×(— 1/3)²

Tentukan hasil dari perpangkatan berikut a. 5+3×2⁴

Bagian a

5 + 3 × 2⁴

= 5 + 3 × (2 × 2 × 2 × 2)

= 5 + 3 × (4 × 4)

= 8 × 16

= 128

$\$

$frac{1}{2} ( {6}^{3} - {4}^{2} )$

$= frac{1}{2} times (( underline{6 times 6 }times 6) - (4 times 4))$

$= frac{1}{2} times ((36 times 6) - 16)$

$= frac{1}{2} times (216 - 16)$

$= frac{1}{ not2} times cancel{200} : ^{100}$

$= bold{100}$

$\$

8 + 3 × (-3)⁴

= 8 + 3 × (-3 × (-3) × (-3) × (-3))

= 8 + 3 × (9 × 9)

= 8 + 3 × 81

= 8 + 243

= 251

$\$

(6⁴ – 4⁴) ÷ 2

= (6 × 6 × 6 × 6 – 4 × 4 × 4 × 4) ÷ 2

= (36 × 36 – 16 × 16) ÷ 2

= (1.296 – 256) ÷ 2

= 1.040 ÷ 2

= 520

$\$

${( frac{1}{2} )}^{4} times {( - frac{1}{3})}^{2}$

$footnotesize = ( frac{1}{2} times frac{1}{2} times frac{1}{2} times frac{1}{2} ) times ( - frac{1}{3} times ( - frac{1}{3}))$

$=( frac{1}{4} times frac{1}{4} ) times frac{1}{9}$

$= frac{1}{16} times frac{1}{9}$

$= bold{frac{1}{144} }$

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