Tolong Jawab yang nomor 8 pliss hanya satu kok

Jawaban:

10 + log 1,41

Penjelasan:

[OH-] = √( Kb . Mb )

=> √( 10^-5 . 2×10^-3 )

=> √ 2×10^-8

=> 1,41×10^-4

pOH = – log [OH-]

pOH = – log 1,41×10^-4

pOH = 4 – log 1,41

pH = 14 – pOH

pH = 14 – ( 4 – log 1,41 )

pH = 10 + log 1,41