Tentukan nilai x yg memenuhi persamaan berikut.
Kakk mohon bantuanya soalnya sekarang di kumpulin.
Jawab:
Penjelasan dengan langkah-langkah:
a.
2x + 4 = 6
2x = 6 – 4
2x = 2
x = 1
b.
3x – 2 = 7
3x = 7 + 2
3x = 9
x = 3
c.
1/2 x + 2 = 4
1/2 x = 4 – 2
1/2 x = 2
x = 2 : 1/2
x = 4
d.
1/3 x – 2 = 1
1/3 x = 1 + 2
1/3 x = 3
x = 3 : 1/3
x = 9
e.
3x – 2 = x + 2
3x – x = 2 + 2
2x = 4
x = 2
f.
1/3 x + 1 = 2x – 4
x + 3 = 6x – 12 ———-> dikalikan 3
x – 6x = -12 – 3
-5x = =15
x = -15/-3
x = 5
g.
2x – 3 / 3 = 3x – 2/6
2 ( 2x – 3 ) = ( 3x – 2 ) ———–> dikalikan 6
4x – 6 = 3x – 2
4x – 3x = -2 + 6
x = 4
h.
1/( x – 2 ) + 1/( 2x – 4 ) = 5/6
1/ ( x – 2 ) + 1 / 2 ( x – 2 ) = 5/6
2/2( x – 2) + 1/2( x – 2 ) = 5/6
3/ 2(x – 2 ) = 5/6
5 ( 2 ( x – 2 ) ) = 3 ( 6 )
10 ( x – 2 ) = 18
10x – 20 = 18
10x = 18 + 20
10x = 38
x = 3,8
i.
(4x – 1)/(x – 2 ) – 1 = 4x – 2
( 4x – 1 ) /( x – 2 ) = 4x – 2 + 1
( 4x – 1 )/ ( x – 2 ) = 4x – 1
4x – 1 = ( x – 2 ) ( 4x – 1 )
( 4x – 1 ) / ( 4x – 1 ) = ( x – 2 )
1 = x – 2
x = 1 + 2
x = 3
j.
( x + 4 )/( x + 3 ) – 1 = 1/5
( x + 4 ) / ( x + 3 ) = 1 + 1/5
( x + 4 ) / ( x + 3 ) = 6/5
5 ( x + 4 ) = 6 ( x + 3 )
5x + 20 = 6x + 18
5x – 6x = 18 – 20
-x = – 2
x = 2
k.
( 2x + 5 ) / ( x + 2 ) – 2 = 1/4
( 2x + 5 ) / ( x + 2 ) = 2 + 1/4
( 2x + 5 ) / ( x + 2 ) = 9/4
4 ( 2x + 5 ) = 9 ( x + 2 )
8x + 20 = 9x + 18
8x – 9x = 18 – 20
-x = -2
x = 2
semoga bisa membantu
Jawaban:
a.2x+4=6
2x=6-4
x=2-2
x=O