Tolong bntu y ini mteri vektor dipkek skrng

Penjelasan dengan langkah-langkah:

AB = B – A

= (1,0,3) – (2,-1,4)

= (-1, 1, -1)

AC = C – A

= (2,0,3) – (2,-1,4)

= (0,1,-1)

AB . AC = (-1 . 0) + (1 . 1) + (-1 . -1)

= 0 + 1 + 1

= 2

|AB| = √(-1)^ + (1)^2 + (-1)^2

= √1 + 1 + 1

|AB| = √3

|AC| = √(0)^2 + (1)^2 + (-1)^2

= √1 + 1

|AC| = √2

misal sudut antara AB dan AC adl a, maka

cos a = AB . AC / |AB| |AC|

= 2 / √3 . √2

= 2/√6

RASIONALKAN

= 2/√6 x √6/√6

= 2/6 √6

= 1/3 √6