A)….+12×….=352B)2x²-12x+8=0
A) 112 + 12 × 20=352
B)2x²-12x+8=0
<=> x²-6x+4 = 0
<=> x²-6x+9+4-9 = 0
<=> (x-3)²+4-9 = 0
<=> (x-3)²= -4+9
<=> (x-3)²= 5
<=> (x-3) = ±√5
x-3 = √5 atau x-3 = -√5
x= 3+√5 atau x= 3-√5
A)….+12×….=352B)2x²-12x+8=0
A) 112 + 12 × 20=352
B)2x²-12x+8=0
<=> x²-6x+4 = 0
<=> x²-6x+9+4-9 = 0
<=> (x-3)²+4-9 = 0
<=> (x-3)²= -4+9
<=> (x-3)²= 5
<=> (x-3) = ±√5
x-3 = √5 atau x-3 = -√5
x= 3+√5 atau x= 3-√5