A. 18 cm2b. 27 cm2c. 45 cm2d. 72 cm2tolong dijawab ya, makasi

LUAS = S²
144 = S²
S = 12 cm
maka
AB = BC = CD = DA = 12 cm
dan
AE = ED = DG = GC = BH = AH = 1/2 x sisi = 6 cm

EH = EG = √(6² + 6²) = 6√2 cm
AF = 1/2 x EH = 1/2 x 6√2 = 3√2 cm
EF = √(AE² – AF²) = √(6² – {3√2}²) = √(36 – 18) = √18 = 3√2 cm
AC = √(12² + 12²) = 12√2 cm
FC = AC – AF = 12√2 – 3√2 = 9√2 cm

luas trapesium
= {(EG + FC) x EF}/2
= {(6√2 + 9√2) 3√2}/2
= {15√2 x 3√2}/ 2
= 15 x 3 x 2/2
= 15 x 3
= 45 cm²

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