A ball is dropped from a height and hits the floor with a speed of 10 m/s. Then the ball bounces up with a speed of 4 m/s. Calculate:

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a. Impulse acting on the ball if the ball has a mass of 0.2 kg (20 poin)
b. The force acting on the floor when the ball hits the floor for 0.01 second (20 poin)​

A ball is dropped from a height and hits the floor with a speed of 10 m/s. Then the ball bounces up with a speed of 4 m/s. Calculate:

Jawaban:

Penjelasan:

a. impulse acting to the ball is equal with the change of linear momentum

I=-Delta P=-m(v_2-v_1)=-0.2kg(4m/s-10m/s)=7.2Ns

b. the average force acting on the floor

I=FDelta t=7.2 Ns=F(0.01s)\F=720N