Ada yang bisa? aku bingung :(

Ada yang bisa? aku bingung 🙁

Terima kasih semoga terbantu

Gambar Jawaban

Gunakan rumus eksponensial
$( frac{a}{b})^{m} = frac{ {a}^{m} }{ {b}^{m} } \ {a}^{ - m } = frac{1}{ {a}^{m} } \ ( {a}^{m} )^{n} = {a}^{m times n}$

11.
$( frac{1}{2} )^{3} + ( frac{2}{3} )^{2} - (3)^{ - 2} \ = frac{ {1}^{3} }{ {2}^{3} } + frac{ {2}^{2} }{ {3}^{2} } - frac{1}{ {3}^{2} } \ = frac{1}{8} + frac{4}{9} - frac{1}{9}$
Sisanya lanjutkan sendiri ya

12.
$( {256}^{ frac{1}{2} })^{ frac{3}{4} } + ( {343}^{2})^{ frac{1}{6} } - ( {512}^{ frac{1}{3} } )^{ frac{4}{3} } \ = {256}^{ frac{1}{2} times frac{3}{4} } + {343}^{2 times frac{1}{6} } - {512}^{ frac{1}{3} times frac{4}{3} } \ = {256}^{ frac{3}{8} } + {343}^{ frac{1}{3} } - {512}^{ frac{4}{9} } \ = ( {2}^{8} ) ^{ frac{3}{8} } + ( {7}^{3} )^{ frac{1}{3} } - ({2}^{9} )^{ frac{4}{9} } \ = {2}^{8 times frac{3}{8} } + {7}^{3 times frac{1}{3} } - {2}^{9 times frac{4}{9} } \ = {2}^{3} + {7}^{1} - {2}^{4} \ = 8 + 7 - 16 \ = - 1$