Akar 5 (pangkat 2x + 1) = 25 (pangkat x) - 2

Akar 5 (pangkat 2x + 1) = 25 (pangkat x) – 2

$sqrt{5} {}^{2x + 1} = 25 {}^{x - 2} \ 5 {}^{ frac{1}{2} (2x + 1)} = 5 {}^{2(x - 2)} : angka : 5 : habis : terbagi \ frac{1}{2} (2x + 1) = 2(x - 2) \ x + frac{1}{2} = 2x - 4 \ x - 2x = - 4 - frac{1 }{2} \ - x = frac{ - 9}{2} \ x = frac{ - 9}{ - 2} \ x = frac{9}{2}$