#pleasee bgt tolong dijawab
Akar akar persamaan y^2 – py + 18 = 0 adalah m dan n. Jika nilai m = 2n, tentukan nilai p !
Jawaban Terkonfirmasi
Bab Persamaan Kuadrat
Matematika SMP Kelas VIII
y^2 – py + 18 = 0
a = 1; b = – p; c = 18
m = 2n
m x n = c/a
2n x n = 18/1
2n^2 = 18
n^2 = 18/2
n = akar 9
n = 3
m = 2n
m = 2 x 3
m = 6
m + n = -b/a
6 + 3 = -(-p)/1
p = 9
atau
n = – 3
m = 2n
m = 2 x (-3)
m = -6
m + n = -b/a
– 6 + (-3) = – (-p)/1
p = – 9
jadi, p = 9 atau p = – 9