Assalamualaikum, mohon bantuannya guys​

Jawab:

-1/3

Penjelasan dengan langkah-langkah:

=lim x->2 [√(3x+3) -√(5x-1) ] /(x-2) x [√(3x+3) +√(5x-1) ]/[√(3x+3) +√(5x-1) ]

= lim x->2 (3x+3-5x+1) /[ (x-2).[√(3x+3) +√(5x-1)] ]

= lim x->2 (-2x+4) /[ (x-2). [√(3x+3) +√(5x-1) ]

= lim x->2 -2/ [√(3x+3) +√(5x-1) ]

Masukkan x =2 ke fungsi:

= -2/[√(3.2+3) +√(5.2-1) ]

= -2/[√9 +√9 ]

= -2/(3 + 3)

= -2/6

= -1/3