Assalamualaikum mohon bantuannya guys

By Admin ReiPosted on December 4, 2022

Assalamualaikum mohon bantuannya guys

Assalamualaikum mohon bantuannya guys

~HaTwoO

→ No. 1

Lim

x → 1

x² + 2
1² + 2
3

____________________________

→ No. 2

Lim

x → 2

x²
2²
( 2.2 )
4

____________________________

→ No. 3

Lim

x → 2

x² – 4 / x³ + 1
2² – 4 / 2³ + 1
4 – 4 / 8 + 1
0

____________________________

→ No. 4

Lim

x → 3

x² + 2x – 15 / x – 3
x + 5
3 + 5
8

${ boxed{ it{ color{blue}{HaTwoO}}}}$

Penjelasan dengan langkah-langkah:

wa'alaikumussalam warahmatullahi wabarakatu

—Nomor 1

$= lim limits_{x to1} ({x}^{2} + 2)$

$= {1}^{2} + 2$

$= 1 + 2$

$= 3$

$:$

$= lim limits_{x to2} {x}^{2}$

$= {2}^{2}$

$= 4$

$:$

$= lim limits_{x to2} frac{ {x}^{2} - 4}{ {x}^{3} + 1}$

$= frac{ {2}^{2} - 4 }{ {2}^{3} + 1}$

$= frac{4 - 4}{8 + 1}$

$= frac{0}{9}$

$= 0$

$:$

$= lim limits_{x to3} frac{ {x}^{2} + 2x - 15 }{x - 3}$

$= lim limits_{x to3} frac{ {x}^{2} + 5x - 3x - 15 }{x - 3}$

$= lim limits_{x to3} frac{x(x + 5) - 3(x + 5)}{x - 3}$

$= lim limits_{x to3} frac{(x + 5) cancel{(x - 3)}}{ cancel{x - 3}}$

$= lim limits_{x to3}(x + 5)$

$= 3 + 5$

$= 8$