Assalamualaikum........mohon bantuannya.......pakai caranya ya.........

Assalamualaikum……..mohon bantuannya…….pakai caranya ya………

Jawab:

Penjelasan dengan langkah-langkah:

notasi sigma

soal jawab

soal 1

ruas kiri =

$sf sum limitx_{k=1}^{n} (k^2) + sum limits_{k= 4}^{n= 3} (2k + 1) =$

$= sf sum limitx_{k=1}^{n} (k^2) + sum limits_{k= 4-3}^{n= 3-3} (2 (k+3) + 1)$

$= sf sum limitx_{k=1}^{n} (k^2) + sum limits_{k= 1}^{n} (2 k+ 7)$

$= sf sum limitx_{k=1}^{n} (k^2 + 2 k+ 7)$

= ruas kanan (terbukti)

soal 2

ruas kiri =

$sf sum limits_{i =1}^{48} (2i+5) + sum limits_{i = 60}^{n+9} (2i- 17)$

$sf = sum limits_{i =1+2}^{48+2} (2 (i-2) +5) + sum limits_{i = 60-9}^{n+9-9} (2(i+9) - 17)$

$sf = sum limits_{i =3}^{50} (2 i+1) + sum limits_{i = 51}^{n} (2i +1)$

$sf = sum limits_{i =3}^{n} (2 i+1)$

= ruas kanan