Bagaimana?mohon bntuanya

N(S) = 20
Bola bernomor Kelipatan 3 yaitu : 3, 6, 9, 12, 15, 18.
n(K) = 6

Peluang
= n(K) / n(S)
= 6 / 20
= 3/10 (C)

n(S) = 20

A = kejadian munculnya bola bernomor kelipatan 3

A = {3,6,9,12,15,18} → n(A) = 6

P = n(A) / n(S)

P = 6 / 20

P = 3 / 10

Jawabannya C