Bagimana caranya hitung PH H+ 5 x 10 pangkat -4 ???
PH = -log [H+]
= – log 5 x 10^-4
= 4 - log 5
PH = -log [H+] = – log 5 x 10pangkat4 = 4 – log 5 = 3,31
Bagimana caranya hitung PH H+ 5 x 10 pangkat -4 ???
PH = -log [H+]
= – log 5 x 10^-4
= 4 - log 5
PH = -log [H+] = – log 5 x 10pangkat4 = 4 – log 5 = 3,31