Bantu bos tugas sekolah

Bantu bos tugas sekolah

Jawab:

$displaystyle y=frac{3x+5}{x+2}\y(x+2)=3x+5\xy+2y=3x+5\xy-3x=5-2y\x(y-3)=5-2y\x=frac{5-2y}{y-3}\f^{-1}(x)=frac{5-2x}{x-3}\\\f^{-1}(-2)=frac{5-2cdot(-2)}{-2-3}\f^{-1}(-2)=frac{5+4}{-5}\f^{-1}(-2)=-frac{9}{5}\\\f^{-1}(2)=frac{5-2cdot2}{2-3}\f^{-1}(2)=frac{5-4}{-1}\f^{-1}(2)=-1$

$displaystyle -2f^{-1}(x)=x\-2cdotfrac{5-2x}{x-3}=x\4x-10=x(x-3)\4x-10=x^2-3x\x^2-7x+10=0\(x-5)(x-2)=0\x=5vee x=2$

Beberapa konsep yang dipakai: