Bantu jawab dong kak

Bantu jawab dong kak

Jawab:

2. 16π

3. 6π

Penjelasan dengan langkah-langkah:

No 2

$begin{aligned}V&=pidisplaystyleintop_2^4(3^2-(sqrt{x})^2) dx\&=pidisplaystyleintop_2^4(9-x) dx\&=pileft[9x-dfrac12x^2right]_2^4\&=pileft[left(9(4)-dfrac12(4)^2right)-left(9(2)-dfrac12(2)^2right)right]\&=pileft[left(36-8right)-left(18-2right)right]\&=pileft[32-16right]\&=16pi end{aligned}$

No 3

$begin{aligned}y&=x^2\x^2&=yend{aligned}$

$begin{aligned}y&=4x^2\x^2&=dfrac14 yend{aligned}$

$begin{aligned}V&=pidisplaystyleintop_0^4(y-dfrac14y) dy\&=pidisplaystyleintop_0^4dfrac34y dy\&=pileft[dfrac34cdotdfrac12y^2right]_0^4\&=pileft[dfrac38y^2right]_0^4\&=pileft[dfrac38(4)^2-dfrac38(0)^2right]\&=6pi end{aligned}$