Bantu jawab soal fisika, poin gede​

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Bantu jawab soal fisika, poin gede​

Bantu jawab soal fisika, poin gede​

Konsep Analisa Mesh

Mesh 1 :

V_1+V_2-E_1=0\\ V_1+V_2=E_1\\ I_IR_1+(I_I+I_{II})R_2=E_1\\ 2I_I+4(I_I+I_{II})=6\\ 2I_I+4I_I+4I_{II}=6\\ 6I_I+4I_{II}=6\\ 3I_I+2I_{II}=3............(1)

Mesh 2 :

V_3+V_2-E_2=0\\ V_3+V_2=E_2\\ I_{II}R_3+(I_I+I_{II})R_2=E_2\\ 2I_{II}+4(I_I+I_{II})=6\\ 2I_{II}+4I_I+4I_{II}=6\\ 4I_I+6I_{II}=6\\ 2I_I+3I_{II}=3...................(2)

Eliminasi persamaan (1) dan (2)

3I_I+2I_{II}=3\ 2I_I+3I_{II}=3

persamaan (1) dikali 2,   persamaan (2) dikali 3

6I_I-4I_{II}=6\ 6I_I-9I_{II}=9

                        –

5I_{II}=-3\\ I_{II}=-frac{3}{5},A=-0,6,A

Substitusi I_{II} ke persamaan (2)

2I_I+3I_{II}=3\\ 2I_I+3times(-frac{3}{5})=3\\ 2I_I-frac{9}{5}=3\\ 2I_I=3+frac{9}{5}=frac{24}{5}\\ I_I=frac{12}{5}=2,4,A

Jadi, kuat arus masing-masing adalah :

I_1=I_I=2,4,A\\ I_2=I_{II}=-0,6,A\\ I_3=I_I+I_{II}=2,4,A-0,6,A=1,8,A