BANTU SOAL PERPANGKATAN

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BANTU SOAL PERPANGKATAN

BANTU SOAL PERPANGKATAN

Penjelasan dengan langkah-langkah:

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~ Bilangan Berpangkat

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1) : {2}^{10} times 32 div {4}^{6}

= {2}^{10} times {2}^{5} div {( {2}^{2} )}^{6}

= {2}^{10} times {2}^{5} div {2}^{12}

= {2}^{10 + 5 - 12}

= {2}^{3}

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2) : frac{ {3}^{5} times {9}^{2} }{27}

= frac{ {3}^{5} times {( {3}^{2}) }^{2} }{ {3}^{3} }

= frac{ {3}^{5} times {3}^{4} }{ {3}^{3} }

= {3}^{5 + 4 - 3}

= {3}^{6}

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3) : frac{ {5}^{7} div {5}^{ - 3} }{25 times {5}^{4} }

= frac{ {5}^{7} div {5}^{ - 3} }{ {5}^{2} times {5}^{4} }

= frac{ {5}^{7 - ( - 3)} }{ {5}^{2 + 4} }

= frac{ {5}^{10} }{ {5}^{6} } = {5}^{10 - 6} = {5}^{4}

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4) : {( sqrt{3}) }^{4} div frac{1}{81}

= {3}^{ frac{4}{2} } div frac{1}{ {3}^{4} }

= {3}^{2} div frac{1}{ {3}^{4} }

= {3}^{2 - 4} = {3}^{ - 2} = frac{1}{ {3}^{2} } = frac{1}{9}

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5) : frac{0.25 times {4}^{3} }{ sqrt[3]{ frac{1}{16} } }

= frac{ frac{1}{4} times {4}^{3} }{ {( frac{1}{16} )}^{ frac{1}{3} } }

= frac{ {4}^{3 - 1} }{( frac{1}{ {4}^{2} }) frac{1}{3} }

= frac{ {4}^{2} }{( {4}^{ - 2} ) {}^{ frac{1}{3} } }

= frac{ {4}^{2} }{ {4}^{ - frac{2}{3} } }

= {4}^{2 - ( - frac{2}{3} )}

= {4}^{2 + frac{2}{3} }

= {4}^{ frac{8}{3} }

semoga membantu

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Detail Jawaban

Mapel : Matematika

Kelas : 9

Materi : Bilangan Berpangkat

Kode soal : 2

Kode kategorisasi : 9.2.1

Jawaban:

1. 2¹⁰ x 2⁵ : (2²)⁶

= 2¹⁰ x 2⁵ : 2¹²

= 2¹⁰+⁵-¹²

= 2³

= 8

2. 3⁵ x (3²)² : 3³

= 3⁵ x 3⁴ : 3³

= 3⁶

= 729

3. 5⁷-(-³) : 5²+⁴

= 5¹⁰-⁶

= 5⁴

= 625

4. (3¹/²)⁴ : 3-⁴

= 3²-(-⁴)

= 3⁶

= 729