Bantu ya, besok dikumpulkan☺
Jawaban Terkonfirmasi
Kelarutan = ((0,58×10^-3)÷58)÷0,1 = 10^-4 M
konsentrasi [OH-] = 2×kelarutan = 2×10^-4 M
pOH = -log2×10^-4 = 4 – log2
pH = 10 + log2
Bantu ya, besok dikumpulkan☺
Kelarutan = ((0,58×10^-3)÷58)÷0,1 = 10^-4 M
konsentrasi [OH-] = 2×kelarutan = 2×10^-4 M
pOH = -log2×10^-4 = 4 – log2
pH = 10 + log2