Bantuin jawab no 6,7,8 dong

No 6)
AE = CG = 10
CE = diagonal ruang = √(4² +3² + 10²) = √(16+9+100) = √125 = 5√5
berarti sin B = de/mi =
AE /CE = 10/(5√5) = (2/5)√5

no 7)
xp = -2/2.1 = -1
yp = (-1)² + 2(-1) + 15
yp = 1 -2 + 15
yp = 14
titik balik maks =(-1,14)

no 8)
a + b = -4
ab = -21

jmlah akar = (a+2) + (b+2) = a+b + 4 = -4+4 = 0
hasil kali akar = (a+2) (b+2) = ab+2(a+b)+4 = -21 + 2(-4) + 4 = -21-8+4 = -25

persamaan kuadratnya jadi =
x² – (jumlah akar)x + hasil kali akar = 0
x² -25 = 0