Bentuk aljabar x (x + 3) – 9 (x – 1) – 1=….

×(×+3) - 9 (×-1) – 1 = 
ײ + 3× – 9× + 9 – 1 = 0
ײ – 6× + 8 = 0
( × – 2 ) ( × – 4 )
× – 2 = 0 ∨ × – 4 = 0
   ×=2     ∨ × = 4

X^2+3x-9x-9-1=x^2-6x-10
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