Bentuk sederhana dari √18+2√72¬√32¬√50
Jawaban Terkonfirmasi
V18 + 2V72 – V32 – V50
= V(9×2) + 2V(36×2) – V(16×2) – V(25×2)
= V9V2 + 2V36V2 – V16V2 – V25V2
= 3V2 + 2×6V2 – 4V2 – 5V2
= 3V2 + 12V2 – 4V2 – 5V2
= (3 + 12 – 4 – 5)V2
= 6V2
Bentuk sederhana dari √18+2√72¬√32¬√50
V18 + 2V72 – V32 – V50
= V(9×2) + 2V(36×2) – V(16×2) – V(25×2)
= V9V2 + 2V36V2 – V16V2 – V25V2
= 3V2 + 2×6V2 – 4V2 – 5V2
= 3V2 + 12V2 – 4V2 – 5V2
= (3 + 12 – 4 – 5)V2
= 6V2