• (5xy + 3)(2xy – 2)
• -6xy(5 – 5y)
• (y³ + 2)(y⁵ – 3)
Bentuk sederhana dari operasi hitung aljabar berikut :
Penjelasan dengan langkah-langkah:
A.
(5xy + 3) (2xy-2)
10x²y² – 10xy + 6xy – 6
10x²y² – 4xy – 6
B.
-6xy (5-5y)
-6xy.5-6xy.(-5y)
-30xy-6xy.(-5y)
-30xy + 30xy²
C.
(y³ + 2) (y⁵ – 3)
y³.y⁵-3y³+2y⁵-2.3
y⁸.-3y³+2y⁵-6
⇔Jawab
– 10x²y² – 4xy – 6
– 30xy² – 30 xy
– y⁸ – 3y³ + 2y⁵ – 6
⇔Penyelesaian
- (5xy + 3)(2xy – 2)
(5xy × 2xy) + (5xy × (-2)) + (3 × 2xy) + (3 × (-2))
10x²y² + (-10xy) + (6xy) + (-6)
10x²y² – 10xy + 6xy – 6
10x²y² – 4xy – 6
- -6xy (5 – 5y)
(-6xy × 5) + (-6xy × (-5y))
-30xy + 30xy²
30xy² – 30 xy
- (y³ + 2)(y⁵ – 3)
(y³ × y⁵) + (y³ × (-3)) + (2 × y⁵) + (2 × (-3))
y³⁺⁵ + (-3y³) + (2y⁵) + (-6)
y⁸ – 3y³ + 2y⁵ – 6