Beraa ml lar NaOH 0,1m yang harus difambahkan kedalam 100ml lar CH3COOH 0,1M. supaya diperoleh larutan penyangga dengan pH = 5.

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ka : ch3cooh = {10}^{ - 5}
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Beraa ml lar NaOH 0,1m yang harus difambahkan kedalam 100ml lar CH3COOH 0,1M. supaya diperoleh larutan penyangga dengan pH = 5.

Jawaban:

Penjelasan:

Rumus larutan buffer asam

pH = 5 –> [H+] = 10^-5

[H+] = Ka x [CH3COOH]/[CH3COO-]

10^-5 = 10^-5 x [CH3COOH]/[CH3COO-]

[CH3COOH] = [CH3COO-]

n CH3COOH = n CH3COO-

misal volume NaOH = v –> n NaOH = 0.1v

n CH3COOH = 0.1 x 100 = 10

      NaOH       +          CH3COOH         –>          NaCH3COO       +         H2O

m      0.1v                         10

b       0.1v                       0.1v                                     0.1v                           0.1v

s                                   10-0.1v                                   0.1v                          0.1v

n CH3COOH = n CH3COO-

10 – 0.1v = 0.1v

v = 50 mL