Berapa gram NaOH yang diperlukan untuk membuat 2 L larutan NaOH 0.1 m ?

Diketahui
Konsentrasi NaOH = 0,1M
Volume air = 2L
Mr NaOH = 40..

ditanyakan = massa NaOH yang diperlukan ..
Konsenrasi = massa/(Mr x V)
0,1 = massa /(40×2)
masa NaOH = 8 gram..

ssemoga membantu ya kak

Mr NaOH = 40
volume = 2 liter = 2000 mL
m = 0,1 m
kita asumsikan ρ = 1 gram/mL
massa NaOH = ?

—

massa air = ρ x v = 1 x 2000 = 2000 gram = 2 kg

mol NaOH = m x massa air (kg)
mol NaOH = 0,1 x 2
mol NaOH = 0,2 mol

massa NaOH = mol NaOH x Mr
massa NaOH = 0,2 x 40
massa NaOH = 8 gram