Berapa nilai angka tersebut

Berapa nilai angka tersebut

Jawaban:

$9x {}^{2} - 6x + 1 = 0 \ frac{1}{9} (9x - 3)(9x - 3) = 0 \ frac{1}{9} times 3 (3x - 1) : : 3(3x - 1) = 0\ (3x - 1)(3x - 1) = 0 \ \ x1 = frac{1}{3} \ x2 = frac{1}{3}$

jadi HP = {1/3}