Berapakah pH larutan asam benzoat (C6H5COOH) 0,1 M jika diketahui Ka= 6,3×10-5
[H+] = √(Ka.Ma)
= √(6,3.10^-5.0,1)
= √(6,3.10^-6)
= 2,5.10^-3
pH = -log[H+]
= -log[2,5.10^-3]
= 3-log2,5
Berapakah pH larutan asam benzoat (C6H5COOH) 0,1 M jika diketahui Ka= 6,3×10-5
[H+] = √(Ka.Ma)
= √(6,3.10^-5.0,1)
= √(6,3.10^-6)
= 2,5.10^-3
pH = -log[H+]
= -log[2,5.10^-3]
= 3-log2,5