Berapakah pH larutan jika konsumsi ion H + sebesar 0,0007 m​

Jawaban:

4 – log 7

Penjelasan:

Konsentrasi ion H+

= 0,0007 M

= 7 x 10^(-4) M

Nilai pH

= – log [H+]

= – log 7 x 10^(-4)

= – log 7 + 4

= 4 – log 7