BIG POINT KAK, harus dikumpulin hari ini juga. TOLONG DIBANTU PAKE CARA YAA

1. tan (x+23) = tan 135 °
2. x+23 = 135 °
3. x = (135-23) ° + k.180 °
4. x = 112 ° + k.180 °
6. k = 0 —> x = 112 °
7. k = 1 —> x = 292 ° (TIDAK MEMENUHI)
8. jawaban 0

x) = cosⁿ (ax + c)

gunakan rumus turunan

→ f'(x) = n. cosⁿ⁻¹ (ax + c). c . – sin (ax + c)

→ f'(x) = 2 . cos (x + π/4) . 1 . – sin (x + π/4)

→ f'(x) = – 2 . cos (x + π/4) . sin (x + π/4)

Ingat, 2 cos a sin b = sin (a+b) – sin (a-b)

→ f'(x) = sin (x + π/4 + x + π/4) – sin (x + π/4 – x – π/4)

→ f'(x) = sin (2x + π/2)

Subtitusi x = π/4 ke turunan tadi

→ f'(π/4) = sin (2(π/4) + π/2)

→ f'(π/4) = sin (π/2 + π/2)

→ f'(π/4) = sin π

→ f'(π/4) = sin 180° = 0

Penjelasan dengan langkah-langkah:

mohon maaf kalau salah