Bila ^7log2=a dan ^2log3=b maka ^49log 98=

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Bila ^7log2=a dan ^2log3=b maka ^49log 98=

Jawaban:

frac{a + 2}{2}

Penjelasan dengan langkah-langkah:

{}^{49} log : 98

= frac{ {}^{2} log : 98}{ {}^{2} log : 49}

= frac{ {}^{2} log : (2 times 7 times 7)}{ {}^{2}log : (7 times 7) }

= frac{ {}^{2} log : 2 + {}^{2} log : 7 + {}^{2} log : 7}{ {}^{2}log : 7 + {}^{2} log : 7 }

= frac{1 + frac{1}{ {}^{7} log : 2} + frac{1}{ {}^{7}log : 2 } }{ frac{ 1}{ {}^{7} log : 2} + frac{1}{ {}^{7} log : 2} }

= frac{1 + frac{1}{a} + frac{1}{a} }{ frac{1}{a} + frac{1}{a} }

= frac{1 + frac{1}{a} + frac{1}{a} }{ frac{1}{a} + frac{1}{a} } times frac{a}{a}

= frac{a + 1 + 1}{1 + 1}

= frac{a + 2}{2}

Semoga Membantu :)