Butuh jawabannya segera ​

Jawaban:

Hukum Kirchoff

Ic = Ia + Ib

ΣE + ΣIR = 0

Loop kiri

-12 + 4Ia + 6Ia + 10Ic = 0

-12 + 10Ia + 10Ic = 0

Loop kanan

-6 + 10Ic = 0  

10Ic = 6

Ic = 6/10 = 0,6 A  

-12 + 10Ia + 10Ic = 0

-12 + 10Ia + 10×0,6 = 0

10Ia = 12-6 = 6

Ia = 0,6

Ic = Ia + Ib

0,6 = 0,6 + Ib

Ib = 0 (arus melewati E2)

Penjelasan: