Bx = x + 3
(a – b) (×) = ײ + 6× +7
a (×) =
b(x) = x+3
(a-b)(x) = x²+6x+7
a(x) – b(x) = x²+6x+7
a(x) = x²+6x+7 + b(x)
a(x) = x²+6x+7 + x + 3
a(x) = x² + 7x + 10
semoga membantu
Bx = x + 3
(a – b) (×) = ײ + 6× +7
a (×) =
b(x) = x+3
(a-b)(x) = x²+6x+7
a(x) – b(x) = x²+6x+7
a(x) = x²+6x+7 + b(x)
a(x) = x²+6x+7 + x + 3
a(x) = x² + 7x + 10
semoga membantu