C.

Jawab:
3y + 2x = -1 (opsi B)

Penjelasan dengan langkah-langkah:

Ditanya garis yg
tegak lurus dgn 4y-6x+10=0
dgn 4y=6x-10
m₁ = 6/4
m₁ = 3/2

Tegak lurus
m₁·m₂ = -1
(3/2)·m₂ = -1
maka
m₂ = -1/(3/2)
m₂ = -1(2/3)
m₂ = -2/3

Melewati (4, -3)
y₁ = -3, x₁ = 4
Maka dgn rumus
y-y₁ = m₂(x-x₁)
y-(-3) = (-2/3)(x-4)
y+3 = (-2/3)x+(8/3)
y = (-2/3)x+(8/3)-3
y = (-2/3)x+(8/3)-(9/3)
y = (-2/3)x-(1/3)
3y = -2x-1
3y + 2x = -1 (opsi B)

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