Carilah fungsi invers dari fungsi berikut :f(x) 2x² – 1/2​

f(x) = 2x² – ½

y = 2x² – ½

y + ½ = 2x²

(y + ½)/2 = x²

akar [(y + ½)/2] = x

x = akar [(y + ½)/2]

f-1(y) = akar [(y + ½)/2]

f-1(x) = akar [(x + ½)/2]

Penjelasan dengan langkah-langkah:

f(x) = 2x² – 1

f(x – 1) = 2(x – 1)² – 1

= 2(x² – 2x + 1) – 1

= 2x² – 4x + 2 – 1

= 2x² – 4x + 1

semoga bermanfaat ya…