2 x + y + 4 z = 16
3 x + 2y + z = 10
x + 3 y + 3 z = 16
Carilah sistem pemecahan dari sistem persamaan berikut (bebas memilih metode)
2x + y + 4z = 16 | x 2 |
4x + 2y + 8z = 32
3x + 2y + z = 10
____________ –
x + 7z = 22 | x 5 |
5x + 35z = 110
2x + y + 4z = 16 | x 3 |
6x + 3y + 12z= 48
x + 3y + 3z = 16
_____________ –
5x + 35z = 110
5x + 9z = 32
___________ –
26z = 78
z = 78 / 26
z = 3
5x + 9z = 32
5x + 9(3) = 32
5x + 27 = 32
5x = 32 – 27
5x = 5
x = 1
2x + y + 4z = 16
2(1) + y + 4(3)= 16
2 + y + 12 = 16
y = 16 – 12 – 2
y = 2
jadi x = 1 , y = 2 , z = 3
Semoga membantu