#DailyQuiz

Jawaban:

bab : fungsi aljabar

f(x) = x/a (1 – b²/x²) + x/b (1 – a²/x²)

maka,

f(x) = x/a (x²/x² – b²/x²) + x/b (x²/x² – a²/x²)

f(x) = (x² – b²)/ax + (x² – a²)/bx

karena x = (a + b), sehingga bisa disubsitusikan ke :

f(a + b) = (x² – b²)/ax + (x² – a²)/bx

f(a + b) = ((a + b)² – b²))/ a(a + b)) + ((a + b)² – a²)) / b(a + b)

f(a + b) = (a² + 2ab + b² – b²) / (a² + ab) + (a² + 2ab + b² – a²)) / (ab + b²)

f(a + b) = (a² + 2ab))/ (a² + ab) + (2ab + b²) / (ab + b²)

f(a + b) = a(a + 2b) / a(a + b) + b(2a + b)/ b(b + a)

f(a + b) = (a + 2b)/ (a + b) + (2a + b)/ (b + a)

f(a + b) = (a + 2b + 2a + b)/ (a + b)

f(a + b) = (3a + 3b) / (a + b)

f(a + b) = 3(a + b)/ (a + b)

f(a + b) = 3

semoga membantu

Jawab:

f(a + b) = 3

Penjelasan dengan langkah-langkah:

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