Dari barisan aritmetika diketahui u2=7 dan u6=19 maka tentukan u8, u12 dan s10​

Jawaban:

u8 = 25

u12 = 37

S10 = 165

Penjelasan dengan langkah-langkah:

U2 = a + b <=> 7 = a + b

U6 = a + 5b <=> 19 = a + 5b

—————————————– –

12 = 4b <=> b = 3

U2 = a + b

7 = a + 3

a = 7-3 = 4

U8 = a + 7b = 4 + 7(3)= 25

U12 = a + 11b = 4 + 11(3) = 37

U10 = a + 9b = 4 + 9(3) = 31

S10 = 10/2 (4 + 31) = 5*35 = 165