Deret bilangan 17-13-43-73-103…… jumlah 16 suku pertama adalah… .
Jawaban Terkonfirmasi
B = -30
a = 17
Un = a + b (n-1)
U16 = 17 – 30 (16-1) = 17 – 450 = – 433
Sn = n/2 (2a + b(n-1)) = n/2 (a + Un)
S16 = 16/2 x (17 – 433)
S16 = 8 x -416
s16 = -3328
Sn= n/2(a+(n-1)b)
Sn= 16/2(17+(16-1)(-30)
Sn= 8(17+(-450)
Sn= 8(433)
Sn= 3464