Diagram 3 shows a composite solid, formed by joining a half m-cylinder with a right prism. ABKJ is the cross - section of the right prism. MK is the diameter of the half - cylinder

Given BK 28 cm, AJ = 14 and AE = 20 cm, The volume of the composite solid is 17000 cm³

Using
$pi = frac{22}{7}$
calculate the value of h

pls help me answer this

Diagram 3 shows a composite solid, formed by joining a half m-cylinder with a right prism. ABKJ is the cross - section of the right prism. MK is the diameter of the half - cylinder

Diagram 3 shows a composite solid, formed by joining a half m-cylinder with a right prism. ABKJ is the cross – section of the right prism. MK is the diameter of the half – cylinder

If you think about composite solid id 17000 cm³, it means that is a combined between half cylinder and trapezium prism. It means in math model:

Volume of half cylinder + volume trapezium prism = 17.000

1/2 π r² t + $(frac{(KB + JA) * BA}{2})$ = 17.000

(Half in volume of half cylinder because that solid is really half not full cylinder)

1/2 * 3,14 * 10 * 10 * 28 + $(frac{(28 + 14) * h}{2})$ = 17.000

(Remember 10 from where? 10 is from 20 that required as radius of a half circle)

(Use a 3,14 to make a solvable result)

1/2 * 314 * 28 + $(frac{42 * h}{2})$ = 17.000

4396 + 21h = 17.000

21h = 17.000 – 4396

21h = 12604

h = 12604 : 21

h = 600,19 cm

So the value of h is 600,19 cm.

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