Dik f(x)=ax=b1

Relasi dan fungsi

f(x) = ax + b

f(-3) = -3
-3a + b = -3……. ( 1 )

f(6) = 42
6a +  b = 42…… ( 2 )

eliminasi nilai b pada pers. ( 1 ) dan ( 2 )
6a + b = 42
-3a + b = -3
—————-  –
9a = 45
a = 45/9
a = 5

subtitusi nilai a = 5 pada pers. ( 2 )
   6a + b = 42
6(5) + b = 42
          b = 42 – 30
          b = 12

f(x) = ax + b 
f(x) = 5x + 12

f(10) = 5x + 12
f(10) = 5(10) + 12
f(10) = 50 + 12
f(10) = 62

semoga membantu