Dik g(x) = x²+x+8 dan (f-g)(x)=2x-3 tentukan

G(x) = x² + x + 8
(f-g)(x) = 2x -3
f(x) – g(x) = 2x -3
f(x) -(x²+x+8) = 2x -3
f(x) -x² – x – 8 = 2x -3
f(x) = x² + 2x + x + 8 -3
f(x) = x² + 3x + 5

a. f(x) = x² + 3x +5
b. f(-2) = (-2)² + 3(-2) + 5
= 4 -6 +5
= 3

g(-2) = (-2)²+(-2)+8
= 4 -2 +8
= 10
c. (f+g)(-2) = x² + 3x + 5 + x² + x + 8
= 2x² + 4x + 13
= 2(-2)² + 4(-2) +13
= 2(4) + (-8) + 13
= 13
(fxg)(-2) = (x² + 3x + 5)(x²+ x + 8)
= ( 4 -6 + 5)(4 -2 + 8)
= (3)(10)
= 30

semoga membantu
maaf kalo salah