Dik log2=a, log 3=b, log 5=c Nyatakan ^75log15 dalam a, b, c

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

^75Log 15
= log 15/log 75
= (log (3 . 5))/(log (3 . 5 . 5))
= (log 3 + log 5)/(log 3 + log 5 + log 5)
= (b + c)/(b + c + c)
= (b + c)/(b + 2c)

Matematika
kelas 10
Logaritma

Diketahui :
log 2 = a
log 3 = b
log 5 = c

Ditanya :
nilai dari ⁷⁵log 15 dalam a, b, c

Jawab :
⁷⁵log 15 = log 15 ÷ log75
              = log (3 x 5) ÷ log (5² x 3)
              = (log 3 + log 5) ÷ (log 5² + log 3)
              = (b + c) ÷ (2c + b)
              = (b + c) ÷ (b + 2c)