Dik pers kuadrat 2x²-6x+14=0 mempunyai akar akar ą dan β hitung ą² + β²
Jawaban Terkonfirmasi
Persamaan kuadrat
2x² – 6x + 14 = 0
a=2,
b = – 6
c = 14
akar akarnya α an β
α+β = -b/a= 3
α.β = c/a = 7
α²+ β² = (α+β)² – 2αβ = 3² – 2(7)= 9-14 = – 5
Dik pers kuadrat 2x²-6x+14=0 mempunyai akar akar ą dan β hitung ą² + β²
Persamaan kuadrat
2x² – 6x + 14 = 0
a=2,
b = – 6
c = 14
akar akarnya α an β
α+β = -b/a= 3
α.β = c/a = 7
α²+ β² = (α+β)² – 2αβ = 3² – 2(7)= 9-14 = – 5