Diketahui ∆ABC dengan susut A 30°sudutB 45°dan BC 12CM tentukan panjang AC dan AB

A / sin A = b / sin B

A / sin A = b / sin Ba / sin 30° = 12 / sin 45°

A / sin A = b / sin Ba / sin 30° = 12 / sin 45°a / (1/2) = 12 / {(1/2)√2}

A / sin A = b / sin Ba / sin 30° = 12 / sin 45°a / (1/2) = 12 / {(1/2)√2} a√2 = 12

A / sin A = b / sin Ba / sin 30° = 12 / sin 45°a / (1/2) = 12 / {(1/2)√2} a√2 = 12 a = 6√2