Diketahui f fungsi dengan f(x)=ax+1 dan f(6)=4 tentukan: bentuk fungsinya, nilai f(2), nilaif(-2)+f(2), bentuk fungsi f(2x-1)

F(6)=6a+1=4
6a=4-1
a=3/6=1/2
f(x)=1/2 x+1
f(2)=1/2 .2+1=1+1=2
f(-2)+f(2)=1/2.(-2)+1 +1/2.2+1=-1+1+1+1=2
f(2x-1)=1/2 (2x-1)+1
=x-1/2+1
=x+1/2

F(x)=ax+1
f(6)= 6a + 1 = 4
6a = 4-1
a = 3/6
a = ½
f(x) = ½x + 1

f(2) = ½(2) + 1 = 2

f(-2)+f(2) = ½(-2) + 1 + 2 = 2

f(2x-1) = (2x – 1)/2 + 1
= 2x/2 – ½ + 1
= x + ½
f(2x-1) = 2x + 1