tentukan ;
a. nilai a dan b
b. persamaan fungsi tersebut
Diketahui fungsi f(2) = ax + b.Jika f(2) = – 2 dan f(3) = 13
Materi : Fungsi dan Relasi
f(x) = ax + b
{ f(2) = -2 } => 2a + b = -2
{ f(3) = 13 } => 3a + b = 13
__________________/
Eliminasi ( b )
2a – 3a = – 2 – 13
– a = – 15
a = 15
()()()()()
b = – 2a – 2
b = – 2( 15 ) – 2
b = – 30 – 2
b = – 32
____________/
Result : a = 15 dan b = – 32
Fungsinya : f(x) = 15x – 32
Semoga bisa membantu
Penjelasan dengan langkah-langkah:
a)
f(2) = 2a + b = – 2
f(3) = 3a + b = 13
_____________ –
a = 15
2(15) + b = – 2
b = – 2 – 30
b = – 32
b) f(x) = 15x – 32