tolong bantuannya besok harus di kumpul
Diketahui Fungsi f(x) =2x – 3 dan g(x) =1/3x + 1 ,X≠-1/3 , tentukan (gof)-¹(x) !
Penjelasan dengan langkah-langkah:
Diket :
f(x) = 2x – 3 dan g(x) = 1 / (3x + 1)
Tentukan fungsi invers (gof)⁻¹(x) !
Jawab :
(gof)(x) = g(f(x))
(gof)(x) = 1 / (3(2x – 3) + 1)
(gof)(x) = 1 / (6x – 8)
y = 1 / (6x – 8)
y(6x – 8) = 1
6xy – 8y = 1
6xy = 8y + 1
x(6y) = 8y + 1
x = (8y + 1)/6y
(gof)⁻¹(x) = (8x + 1)/6x
Semoga Bermanfaat