Diketahui fungsi f(x) = x²-2x+3 dan g (x) = 4-x. tentukan (fog) (0)=….​

f(x) = (x² – 2x + 3)

g(x) = (4 – x)

(fog)(x) = f(g(x))

(fog)(x) = f(4 – x)

(fog)(x) = (4 – x)² – 2•(4 – x) + 3

(fog)(x) = (x² – 8x + 16) – 8 + 2x + 3

(fog)(x) = x² – 8x + 16 – 8 + 2x + 3

(fog)(x) = x² – 8x + 2x + 16 – 8 + 3

(fog)(x) = x² – 6x + 11

(fog)(0) = (0)² – 6•0 + 11

(fog)(0) = 0 – 0 + 11

(fog)(0) = 11