Diketahui fungsi f(x)=2x-1 dan g(x)=4x²-1.tentukan fungsi fungsi

f(x) = (2x – 1)

g(x) = (4x² – 1)

(f + g)(x) = f(x) + g(x)

(f + g)(x) = (2x – 1) + (4x² – 1)

(f + g)(x) = 2x – 1 + 4x² – 1

(f + g)(x) = 4x² + 2x – 1 – 1

(f + g)(x) = 4x² + 2x – 2

(f – g)(x) = f(x) – g(x)

(f – g)(x) = (2x – 1) – (4x² – 1)

(f – g)(x) = 2x – 1 – 4x² + 1

(f – g)(x) = 1 – 1 + 2x – 4x²

(f – g)(x) = 0 + 2x – 4x²

(f – g)(x) = 2x – 4x²

(f • g)(x) = f(x) • g(x)

(f • g)(x) = (2x – 1) • (4x² – 1)

(f • g)(x) = (2x)•(4x²) + (2x)•(-1) + (-1)•(4x²) + (-1)•(-1)

(f • g)(x) = 8x³ + (-2x) + (-4x²) + 1

(f • g)(x) = 8x³ – 4x² – 2x + 1